Final answer:
Calculating the expected DC output voltage of a half-wave rectifier connected to a transformer with a 230V, 50Hz AC input and a 10:1 turns ratio, the correct answer is approximately 15V.
Step-by-step explanation:
The question involves calculating the performance parameters of a half-wave rectifier (HWR) connected to the secondary of a transformer with an input AC voltage of 230V at 50Hz and a turns ratio of 10:1. Given the turns ratio, the voltage on the secondary side of the transformer before rectification would be 230V / 10 which is 23V.
After rectification with a half-wave rectifier, we usually expect the output voltage to be approximately 0.45 times the peak voltage of the secondary side to account for diode drops. The peak voltage of the secondary is given by 23V * √2 (since Vrms * √2 = Vpeak for a sine wave), which is approximately 32.55V. Therefore, the expected DC output voltage after the half-wave rectification is approximately 32.55V * 0.45, which is close to 15V. So the correct performance parameter for the DC output voltage of the rectifier is approximately 15V, which corresponds to option C).