Final answer:
Approximately 1.85 × 10²µ molecules of O₂ are required to react with 4.71 moles of C₄H₁₀, which is not one of the options provided.
Step-by-step explanation:
To determine how many molecules of O₂ are required to react with 4.71 moles of C₄H₁₀, we first need to know the balanced chemical equation for the combustion of butane (C₄H₁₀). The balanced equation is:
2 C₄H₁₀ + 13 O₂ → 8 CO₂+ 10 H₂O
This equation shows that 2 moles of butane react with 13 moles of oxygen. To find the number of moles of O₂ required for 4.71 moles of C₄H₁₀, we set up a proportion:
(4.71 moles C₄H₁₀) x (13 moles O₂ / 2 moles C₄H₁₀) = 30.715 moles O₂
Now we convert moles of O₂ to molecules using Avogadro's number:
30.715 moles O₂ x (6.022 × 10²³ molecules/mol) ≈ 1.85 × 10²µ molecules O₂
So, approximately 1.85 × 10²µ molecules of O₂ are required to react with 4.71 moles of C₄H₁₀. Therefore, the correct answer is none of the above.