Question

when a reverse gate voltage of 15v is applied to a jfet, the gate current is 10⁻³ micro ampere. find the resistance between source and gate

Answer 1

The resistance between the source and gate of a JFET when a reverse gate voltage of 15V is applied and the gate current is 10⁻³ microamperes is found using Ohm's Law and is calculated to be 150 kΩ.

Step-by-step explanation:

To find the resistance between the source and gate of a JFET when a reverse gate voltage of 15V is applied, and the gate current is 10⁻³ microamperes, we use Ohm's Law, which states that resistance is equal to voltage divided by current (R = V/I).

First, we need to convert the gate current from microamperes to amperes.

Since there are 1,000,000 microamperes in an ampere, this means 10⁻³ microamperes is equivalent to 10⁻¹ amperes (since 10⁻³ × 10⁻⁶ = 10⁻¹).

Now, we can calculate the resistance (R) as follows:

R = V/I = 15V / 10⁻¹ A

= 15 × 10⁹ Ω

= 150 kΩ

Therefore, the resistance between the source and gate is 150 kΩ.