Question

In a step-up transformer the voltage in the primary is 220Vand the current is 5A. The secondary voltage is found to be 22000V. The current in the secondary (neglect losses)is

A. 5A
B. 50A
C. 500A
D. 0.005A

Answer 1

Using the power equivalence in an ideal transformer, the current in the secondary coil is calculated to be 0.05 A. However, considering a possible typo in the options, the closest provided answer would be 0.005 A.

Step-by-step explanation:

The question involves the concept of a step-up transformer in physics. Given that the primary voltage is 220V and the current is 5A, and the secondary voltage is 22000V, we use the relationship between the primary and secondary coils of a transformer to find the secondary current.

Power input and power output are equal for an ideal transformer (neglecting losses). So:

• Pp = IpVp
• Ps = IsVs
• Pp = Ps

Substituting the known values:

• (5 A)(220 V) = (Is)(22000 V)
• Is = (5 A)(220 V) / (22000 V)
• Is = 0.05 A

Therefore, the current in the secondary coil is 0.05 A, which is not exactly one of the options provided. Likely there's a typo in the offered choices; the correct answer closest to 0.05 A would be 0.005 A (Option D). Please double-check the options provided.