5.0k views
3 votes
The following grammar generates the language of regular expression : 0*1 (0+1) :

S ---> A1B
A ---> 0A |
B ---> 0B | 1B
For the string 010101, give the leftmost derivation and parse tree.

User Stamat
by
8.3k points

1 Answer

4 votes

Final answer:

The leftmost derivation for the string 010101 is provided along with the corresponding parse tree. The leftmost derivation for the string 010101 using the given grammar can be sequentially found by replacing the leftmost non-terminal in each step, resulting in the clear production steps. The parse tree corresponds to these steps, visually representing the structure of the derivation from the start symbol to the terminals.

Step-by-step explanation:

The leftmost derivation for the string 010101 in the given grammar is as follows:

S -> A1BA -> 0A1BA -> 0101BA -> 0101B -> 0A1B -> 01B -> 0A1B -> 0AB -> 0B -> 010101

The parse tree for the string 010101 can be represented as:

[S [A [0]] [1] [B [0]] [A [1]] [B [0]] [A [1]] [B [0]]]

The leftmost derivation for the string 010101 using the given grammar can be sequentially found by replacing the leftmost non-terminal in each step, resulting in the clear production steps. The parse tree corresponds to these steps, visually representing the structure of the derivation from the start symbol to the terminals.

The question asks us to provide the leftmost derivation and parse tree for the string 010101 generated by the given grammar 0*1 (0+1). A leftmost derivation starts by replacing the leftmost non-terminal symbol at each step. The parse tree visually represents this derivation by branching from the start symbol to the terminals (input symbols).

Leftmost Derivation

Here is the leftmost derivation for the string 010101:

S → A1B

Parse Tree

Start with S as the root.

Proceed to replace A and B with their respective derivations until the tree corresponds to the given string 010101.

This parse tree would show a structured hierarchy starting from S and ending with the terminals (0s and 1s).

User Zoran Zaric
by
8.5k points