17.6k views
1 vote
joel invested 44,000 into two accounts. the amount he put in his money market account was 1,000 less than twice what he put into a cd. how much did he invest in each account?

User Crobzilla
by
9.0k points

1 Answer

3 votes

Final answer:

Joel invested $15,000 in a CD and $29,000 in a money market account, to total $44,000. The amounts were determined by solving the equation which was based on the information that the money market investment is $1,000 less than twice the CD investment.

Step-by-step explanation:

Joel invested $44,000 into two accounts: a money market account and a CD (Certificate of Deposit). Let's define the amount he put into the CD as x. According to the problem, the amount he put into the money market account is $1,000 less than twice the amount put into the CD, so it can be written as 2x - $1,000.We can set up the following equation to represent the total investment:

x (amount in CD) + (2x - $1,000) (amount in money market) = $44,000

By solving the equation, we can determine how much Joel invested in each account:

  • x + 2x - $1,000 = $44,000
  • 3x - $1,000 = $44,000
  • 3x = $45,000
  • x = $15,000

This means Joel invested $15,000 in the CD. To find the amount in the money market account:

2($15,000) - $1,000 = $30,000 - $1,000 = $29,000

Therefore, Joel invested $15,000 in the CD and $29,000 in the money market account.

User Jlanza
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.