Explanation:
we have
f(x) = y = 2x² - 4x - 6
for a quadratic function
f(x) = ax² + bx + c
the x-coordinate of the vertex is
x = -b/(2a)
the y-coordinate is then
y = f(x)
so, in our case
a = 2
b = -4
c = -6
x = - -4/(2×2) = 4/4 = 1
y = f(1) = 2×1² - 4×1 - 6 = 2 - 4 - 6 = -8
the vertex is (1, -8).