Final answer:
The chemical reaction in question is between Fe2(SO4)3 and KOH to yield K2SO4 and Fe(OH)3. This is a double displacement reaction, which has been balanced to clearly represent the stoichiometry of the reactants and products.
Step-by-step explanation:
The question revolves around a chemical reaction involving iron(III) sulfate (Fe2(SO4)3) and potassium hydroxide (KOH) to produce potassium sulfate (K2SO4) and iron(III) hydroxide (Fe(OH)3).
This type of reaction is called a double displacement or metathesis reaction, characterized by the exchange of ions between the reacting compounds.
To balance this particular equation, it's necessary to first write out the unbalanced formula:
Fe2(SO4)3 + KOH → K2SO4 + Fe(OH)3
The next step is to balance the equation by ensuring there are equal numbers of each type of atom on both sides of the equation. After balancing the reaction, we get:
Fe2(SO4)3 + 6KOH → 3K2SO4 + 2Fe(OH)3
This indicates that six moles of potassium hydroxide react with one mole of iron(III) sulfate to produce three moles of potassium sulfate and two moles of iron(III) hydroxide.