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write the equation of the line in slope intercept from that is perpendicular to y=5x-2 and goes through the point (5,-3)

User Theyetiman
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1 Answer

1 vote

Answer:y = (-1/5)x - 2.

Explanation:

1. Determine the slope of the given line bookie.

The given line is in slope-intercept form, y = mx + b, where m represents

the slope. In this case, the slope is 5.

2. Find the slope of the line perpendicular to the given line.

Perpendicular lines have slopes that are negative reciprocals of each

other. So, the slope of the perpendicular line is -1/5.

3. Use the point-slope form to write the equation.

The point-slope form of a linear equation is y - y, = m(x-X1), where (x1, Y1)

represents the coordinates of the given point and m is the slope of the

line.

Plugging in the values, we have:

y - (-3) = (-1/5) (x-5)

Simplifying further:

V+3=(-1/51×+1

Finally, isolate y on one side of the equation:

y = (-1/5)x - 2

Therefore, the equation of the line that is perpendicular to y = 5x - 2 and

passes through the point (5, -3) is y = (-1/5)x - 2.

User Khushneet
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