Question

7.
(-3x³)(-2x³y⁴z)(-3z²)÷(4x³z)(-3yz) (-3xyz)​

Answer 1

`-(x^2y^2)/(2)`

Explanation:

We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :

Remove the parenthesis to make it easier to read :

`(-3x^3 *2x^3y^4z *3z^2)/(4x^3z*3yz*3xyz)`

Multiply the numerators :

`(-18x^6y^4z^3)/(4*3*3x^3yyzzz)`

Multiply the denominators :

`(-18x^6y^4z^3)/(36x^4y^2z^3)`

Apply the negative rule :

`-(18x^6y^4z^3)/(36x^4y^2z^3)`

Cancel the common factor which is 18 :

`-(x^6y^4z^3)/(2x^4y^2z^3)`

Apply the addition exponent rule :

`(y^4z^3x^(6-4) )/(2y^2z^3)`

Subtract :

`(x^2y^4z^3 )/(2y^2z^3)`

Apply the rule for y :

`(x^2y^(4-2) z^3 )/(2z^3)`

Subtract :

`(x^2y^2z^3 )/(2z^3)`

Cancel the common factor of z^3 :

`-(x^2y^2)/(2)`