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A solution in a container is labeled as being a 1 molar aqueous solution, but the rest of the label is ripped off. You measure the volume in a beaker and determine that it is 0.5 liters and you find the mass as 531g. Make an educated guess on what the solute could be. Explain your reasoning.

User Mscccc
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Final answer:

To estimate the solute in a 1 molar solution with a volume of 0.5 liters and a mass of 531g, calculate the molar mass by dividing the mass by the number of moles. With a result of 1062 g/mol, the substance could be a compound with a heavy element or large molecular structure, but the actual molar mass might be overestimated if the container's mass was included.

Step-by-step explanation:

Estimating the Solute in a Solution

To make an educated guess about the identity of the solute in a 1 molar solution with a volume of 0.5 liters and a mass of 531g, we need to calculate the molar mass of the solute.

First, we can determine the number of moles of solute in the solution by using the formula for molarity, which is moles of solute per liter of solution (mol/L). Since the solution is 1 molar, we know there are 1 mole of solute per liter. Therefore, for 0.5 liters, there would be 0.5 moles of solute.

Next, to find the molar mass, we divide the mass of the solute (531g) by the amount in moles (0.5 moles):

molar mass = 531g / 0.5 moles

= 1062 g/mol.

This large molar mass suggests the solute could be a compound with a heavy element or a large molecular structure. Considering the most common substances used in laboratories, one possible solute could be lead(II) nitrate (Pb(NO3)2), which has a molar mass of approximately 331.2 g/mol.

However, this estimation exceeds the calculated molar mass significantly, meaning that our solution may contain a solute with an even greater molar mass, or that the measured mass might include the mass of the solution and the container, which is not accounted for in this calculation.

User Andy Mudrak
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