Question

An experiment was found to have a SEP of 10% and a sample proportion of 80%. What was the size of the sample, n?

Answer 1

16

Explanation:

The sample proportion (p-hat) is given as 80%, which can be written as 0.80. The standard error of the proportion (SEP) is given as 10%, which can be written as 0.10.

The formula for the standard error of a proportion is:

SEP = sqrt((p-hat * (1 - p-hat)) / n)

We can rearrange the formula to solve for the sample size (n):

n = (p-hat * (1 - p-hat)) / (SEP^2)

Substituting the given values into the formula, we have:

n = (0.80 * (1 - 0.80)) / (0.10^2)

Simplifying the equation:

n = (0.80 * 0.20) / 0.01

n = 0.16 / 0.01

n = 16

Therefore, the size of the sample (n) is 16.