Final answer:
The mass of the liquid formed would be the same as the combined mass of the reactants, which is 22 g. To determine the mass of the liquid formed, we need to calculate the amount of each substance that has reacted completely. By comparing the mole ratios between the reactants and the product, we can determine the limiting reactant and calculate the mass of the liquid formed. In this case, the mass of the liquid formed would be the same as the combined mass of the reactants.
Step-by-step explanation:
In this reaction, 10g of a substance reacts with 12g of a second substance to form a liquid.
To determine the mass of the resulting liquid, we need to calculate the amount of each substance that has reacted completely.
From the given masses, we can convert them into moles by dividing by the molar mass of each substance.
Next, we compare the mole ratios between the two substances in the balanced equation to determine the limiting reactant, which is the one that produces the lesser amount of product.
The mass of the liquid formed will then be calculated by multiplying the mole ratio of the liquid to the limiting reactant by its molar mass.
Let's use an example to illustrate this:
Suppose the balanced equation is: A + B -> Liquid
Molar mass of A = 10 g/mol
Molar mass of B = 12 g/mol
To calculate the moles of A, we divide its mass by its molar mass:
Moles of A = 10 g / 10 g/mol
= 1 mol
To calculate the moles of B, we divide its mass by its molar mass:
Moles of B = 12 g / 12 g/mol
= 1 mol
Since the mole ratio of A to B is 1:1 in the balanced equation, both substances are the limiting reactant.
Therefore, the mass of the liquid formed would be the same as the combined mass of the reactants, which is 10 g + 12 g = 22 g.