Question

A \[4.5\,\text{kg}\] firework explodes into two pieces, which fly horizontally in opposite directions. Piece 1 has a mass of \[0.5\,\text{kg}\] and a velocity of \[-48\,\dfrac{\text{m}}{\text{s}}\]. Piece 2 has a mass of \[4.0\,\text{kg}\]. What is the velocity of piece 2?

Answer 1

6.0 m/s

Step-by-step explanation:

Initial horizontal momentum = final horizontal momentum

0 = m₁ v₁ + m₂ v₂

0 = (0.5 kg) (-48 m/s) + (4.0 kg) v

v = 6.0 m/s