To find the molar mass of each compound, you need to calculate the sum of the atomic masses for all the atoms in the compound. For example, the molar mass of HF is 20.01 g/mol, NH3 is 17.03 g/mol, HNO3 is 63.02 g/mol, Ag2SO4 is 303.33 g/mol, and B(OH)3 is 61.83 g/mol.
The molar mass of a compound is calculated by adding up the atomic masses of all the atoms in the compound. Let's find the molar mass for each of the given compounds:
a) Hydrogen fluoride, HF:
H = 1.01 g/mol
F = 19.00 g/mol
Molar mass of HF = 1.01 g/mol (H) + 19.00 g/mol (F) = 20.01 g/mol
b) Ammonia, NH3:
N = 14.01 g/mol
H = 1.01 g/mol
Molar mass of NH3 = 14.01 g/mol (N) + 1.01 g/mol (H) x 3 (since there are 3 hydrogen atoms) = 17.03 g/mol
c) Nitric acid, HNO3:
H = 1.01 g/mol
N = 14.01 g/mol
O = 16.00 g/mol
Molar mass of HNO3 = 1.01 g/mol (H) + 14.01 g/mol (N) + 16.00 g/mol (O) x 3 (since there are 3 oxygen atoms) = 63.02 g/mol
d) Silver sulfate, Ag2SO4:
Ag = 107.87 g/mol
S = 32.07 g/mol
O = 16.00 g/mol
Molar mass of Ag2SO4 = 107.87 g/mol (Ag) x 2 (since there are 2 silver atoms) + 32.07 g/mol (S) + 16.00 g/mol (O) x 4 (since there are 4 oxygen atoms) = 303.33 g/mol
e) Boric acid, B(OH)3:
B = 10.81 g/mol
O = 16.00 g/mol
H = 1.01 g/mol
Molar mass of B(OH)3 = 10.81 g/mol (B) + 16.00 g/mol (O) + 1.01 g/mol (H) x 3 (since there are 3 hydrogen atoms) = 61.83 g/mol