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With an acceleration of 5.3m/s^2 and a final velocity of 36.2m/s, how long did it take the object to reach the Vf?

2 Answers

5 votes

Answer: 36.2/5.3 = 6.83s

Step-by-step explanation:

we can use v = u + at

v = final velocity = 36.2 ms-1

u= Initial velocity = 0

a= acceleration = 5.3 ms-2

t= time = ?

36.2 = 5.3t

t = 36.2/5.3

t= 6.83s

hope this helps

User Manish Goel
by
8.1k points
2 votes

Answer:

6.8 s

Step-by-step explanation:


t=(36.2)/(5.3) =6.83s

Hope this helps.

User Jon Archway
by
7.7k points