Final answer:
The translation of mRNA sequences into amino acids requires using a codon table, reading the triplets from the 5' to 3' end. For the provided sequences, two encode the sequence Ser-Ala-Asn-Leu-Val, and one encodes Ser-Ala-Asn followed by a Stop codon, due to the redundancy of the genetic code.
Step-by-step explanation:
The question involves the process of translation of an mRNA template into an amino acid sequence by using the genetic code. To determine which mRNA sequence would create a specific amino acid sequence, one must refer to the codon table which maps each triplet of nucleotides (codon) to their corresponding amino acid. The codons must be read from the 5' end to the 3' end, which reflects the N-terminal to C-terminal direction of protein synthesis.
Here are the amino acid sequences encoded by the given mRNA sequences:
- Ser-Ala-Asn-Leu-Val: 5'-UCG-GCA-AAU-UUA-GUU-3'
- Ser-Ala-Asn-Leu-Val: 5'-UCU-GCA-AAU-UUA-GUU-3'
- Ser-Ala-Asn-Stop: 5'-UCU-GCA-AAU-UAA-GUU-3' (The UAA codon signals for the termination of translation, resulting in a shorter peptide sequence.)
The correct mRNA sequence must be chosen based on the desired amino acid sequence given. Remember that there can be more than one correct mRNA sequence for an amino acid sequence due to the redundancy of the genetic code, where multiple codons can code for the same amino acid.