Final answer:
The truth value of s ∨ ~s is true if s is true, as the logical disjunction is true when at least one of the statements is true, conforming to the law of excluded middle.
Step-by-step explanation:
If s is true, the truth value of s ∨ ~s is also true. This is because in logical disjunction (represented by the symbol ∨, which means 'or'), the compound statement is true if at least one of the individual statements is true. Since s is given as true, and ~s represents the negation of s, which would be false if s is true, the disjunction s ∨ ~s is true regardless of the truth value of ~s. This follows the principle of the law of excluded middle, which asserts that for any proposition, either that proposition is true or its negation is true.