Final answer:
At the checkpoint in the race, Car A, which starts from rest and accelerates constantly, will be traveling faster than Car B, which travels at a constant speed. The suggested equation V = KVO is not consistent with Car A's motion, as its initial velocity is zero and thus doesn't show increasing velocity. Graphing these motions would show an upward curve for Car A's velocity and a horizontal line for Car B's constant velocity.
Step-by-step explanation:
Two cars are in a race, and according to the graph showing changes in speed with time, we need to determine their motion at time t. When evaluating the motion of the cars, we must consider velocity and acceleration. Car A starts from rest and accelerates constantly, while Car B moves at a constant speed. If the cars reach the checkpoint simultaneously, with Car A starting from rest, at the checkpoint Car A must have a greater velocity than Car B because it must compensate for the initial period during which it was at rest and picking up speed.
The equation V = KVO where K is a constant and VO is the initial velocity of Car B, is not consistent with our observation that Car A has a constant acceleration from rest. Therefore, the initial velocity of Car A (VO) is zero, and the equation V = KVO would incorrectly imply that Car A's velocity at the checkpoint is also zero, which is not possible if it reached the checkpoint at the same time as Car B. In graphing the velocities, Car A's graph would show a line curving upwards as its velocity increases with distance due to constant acceleration, while Car B's graph would be a straight horizontal line representing constant velocity.