Final answer:
A total of 6 different 3-digit numbers can be made using the digits 5, 3, and 2, by calculating the factorial of the number of digits (3! = 3 x 2 x 1 = 6).
Step-by-step explanation:
The question is asking how many different 3-digit numbers can be made using the digits 5, 3, and 2, with each digit being used only once in each number.
To find the number of different combinations, we can use what's known as factorial notation. For a three-digit number, there are 3 choices for the first digit, 2 choices for the second digit (after the first digit has been chosen), and finally 1 choice for the last digit (after the first two digits have been chosen). The total number of different 3-digit numbers we can make is therefore 3 x 2 x 1 = 6. This is the same as calculating 3! (three factorial), which also equals 6.
Examples of 3-digit numbers