Rouding to two decimal places, the solution is approximately x≈−0.36.
To solve the equation e^x =0.7, you can take the natural logarithm (ln) of both sides:
ln(e^x )=ln(0.7)
Using the property
ln(e^a )=a, the equation simplifies to:
x=ln(0.7)
Now, you can calculate the numerical value:
x≈ln(0.7)
Using a calculator:
x≈−0.35667
Rouding to two decimal places, the solution is approximately x≈−0.36.