Question

A and B are two towns 360kms apart. An express bus departs from A at 8am and maintains an average speed of 90km/h btwn A and B. Another bus starts from B also at 8AM and moves towards A making four stops at four equally spaced points between B and A. Each stop is of duration 5 minutes and the average speed between any two stops is 60km/h. Calculate the distance between two buses at 10am

Answer 1

First bus: (90 km/h)(2 hrs) = 180 km

Second bus:

360 km/5 points = 72 km/point

72 km ÷ (60 km/hr) = 1.2 hr =

1 hr, 12 min

2 hr - (1 hr 12 min + 5 min) =

2 hr - 1 hr 17 min = 43 min

(60 km/hr)(43/60 hr) = 43 km

72 + 43 = 115 km

360 km - 115 km = 245 km

Distance between buses:

245 km - 180 km = 65 km

Answer 2

At 10am, the distance between the two buses is 0 km, meaning they are at the same position.

Step-by-step explanation:

To calculate the distance between the two buses at 10am, we need to determine the positions of each bus at that time.

The express bus from town A maintains a constant speed of 90 km/h, so it would have traveled for 2 hours until 10am and covered a distance of 180 km (90 km/h x 2 h).

The other bus starts from town B and travels at an average speed of 60 km/h between stops. With five minutes at each stop, the total time from 8am to 10am is 2 hours and 10 minutes.

As the four stops are spaced equally, there are five intervals between them.

The average speed between stops is 60 km/h, so each interval would take (360 km - 180 km) / (5 intervals)

= 36 km.

Therefore, at 10am, the second bus would have traveled for 2 hours and 10 minutes, covering a distance of 5 intervals x 36 km

= 180 km.

The distance between the two buses at 10am is the difference in their positions, which is :

180 km - 180 km = 0 km.

Therefore, the two buses are at the same position at 10am.