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How many liters each of a 55% acid solution and a 75% acid solution must be used to produce 40 liters of a 65% acid solution? (Round to two decimal places if necessary.)

User Rohanie
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2 Answers

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Answer:

.75x + .50(40 - x) = .65(40)

.75x + 20 - .50x = 26

.25x = 6

x = 24 liters of 75% acid solution

40 - 24 = 16 liters of 50% acid solution

User Deor
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Final answer:

To find the appropriate volumes of 55% and 75% acid solutions needed to create a 65% acid solution, a system of linear equations must be solved, which aligns with the subject of mathematics at the high school level.

Step-by-step explanation:

The question involves a system of linear equations which is a concept within algebra, a branch of mathematics. To determine how many liters of a 55% acid solution and a 75% acid solution are needed to create 40 liters of a 65% acid solution, we can set up two equations based on the principles of concentration and volume. Let's denote the volume of the 55% solution as x liters and the volume of the 75% solution as y liters.

The first equation represents the total volume of the mixture: x + y = 40. The second equation relates to the amount of acid in the final solution: 0.55x + 0.75y = 0.65 × 40. Solving this system of equations, we can find the values of x and y that satisfy both equations. Once we have the solution to the system, we round off to two decimal places if needed to find the exact volume required for each solution.

User Paulchen
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