Question

If the initial conditions of a gas are a pressure of 120 kPa, a volume of 23 liters, and a temperature of 200 K, and then the pressure is raised to 140 kPa and the temperature is increased to 300 K, what is the new volume of the gas using the combined gas law?

a. 140 kPa
b. 140 L
c. 29.6 L
d. 300 K

Answer 1

The new volume of the gas using the combined gas law is 29.6 L.

The answer is option ⇒c

Step-by-step explanation:

The combined gas law is used to relate the initial and final conditions of a gas when pressure, volume, and temperature change.

In this case, the initial conditions are P₁ = 120 kPa, V₁ = 23 L, and T₁ = 200 K, and the final conditions are P₂ = 140 kPa and T₂ = 300 K.

The formula for the combined gas law is:

P₁V₁/T₁= P₂V₂/T₂

Substituting the values into the formula:

(120 kPa)(23 L)/(200 K) = (140 kPa)V₂/(300 K)

Solving for V₂:

V₂ = (120 kPa)(23 L)(300 K)/(140 kPa)(200 K) = 29.6 L

The answer is option ⇒c. 29.6 L