Final answer:
The probability of selecting two men from a group of 5 men and 4 women without replacement is 5/18 or approximately 27.78%.
Step-by-step explanation:
To find the probability that both individuals selected from the group are men, we can use the hypergeometric distribution. The hypergeometric distribution is used when we are sampling from a population composed of two groups without replacement, which is the case here.
Firstly, we calculate the total number of ways to select two individuals from the group of 9 people (5 men and 4 women). This can be done using the combination function C(n, k), which is the number of ways to choose k items from n without regard to order.
There are C(9, 2) ways to choose any 2 individuals from the group, which equals 36.
Next, we find the number of ways to select 2 men from the 5 men available, which is C(5, 2). This equals 10. Therefore, the probability is the number of ways to choose two men divided by the total number of ways to choose two individuals from the entire group.
So, the probability is P = C(5, 2) / C(9, 2) = 10 / 36 = 5 / 18 or approximately 0.2778.
This means that the probability of selecting two men is about 27.78%.