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A cinderblock at rest is knocked off the rooftop of a building and falls for 2.81 seconds. How far did it fall?

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Final answer:

To find the distance fallen by a cinderblock, the kinematic equation d = 0.5 * g * t^2 is used with g=9.81 m/s^2 and t=2.81 s, resulting in a distance of approximately 38.73 meters.

Step-by-step explanation:

To calculate the distance that the cinderblock fell, we can use the kinematic equation for an object under uniform acceleration due to gravity. The equation used is d = 0.5 * g * t^2, where d is the distance, g is the acceleration due to gravity (9.81 m/s2), and t is the time the object is in free fall. We're given that the cinderblock falls for 2.81 seconds.

Distance fallen: d = 0.5 * 9.81 m/s2 * (2.81 s)2

Performing the calculation gives:
d = 0.5 * 9.81 * 2.812
d = 38.73 meters (rounded to two decimal places)

Therefore, the cinderblock falls approximately 38.73 meters.

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