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When Jeff turned 6, he got an allowance and opened a bank account. He deposited $10 to start with and consistently saved $5 each week. Jeff wants to know how much money he will have saved, y, after x number of years.

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Final answer:

Jeff calculates his savings, y, after x years by adding his initial $10 deposit to his weekly savings of $5 for 52 weeks each year, which results in y = 10 + (260 × x).

Step-by-step explanation:

Jeff wants to know how much money he will have saved, y, after x number of years. To calculate this, we need to account for his initial deposit and consistent weekly savings. Jeff deposited $10 to start with and saves $5 each week. There are 52 weeks in a year, so Jeff saves 5 × 52 = $260 per year. After x years, this amount becomes 260 × x.

Jeff's total savings after x years can be found by adding his initial deposit to the total yearly savings. The formula is:

y = 10 + (260 × x)

Substitute any value of x for the number of years Jeff has been saving to find the total amount saved, y.

To calculate how much money Jeff will have saved after x number of years, we need to consider the initial deposit of $10 and the consistent savings of $5 each week. Jeff saves $5 each week, which means he saves $5 * 52 weeks in a year = $260 per year. So, after x number of years, Jeff will have saved $260 * x.

To calculate how much money Jeff will have in total, we need to add the initial deposit of $10 to the savings. Therefore, the formula to calculate the total savings after x years is:

Total Savings (y) = Initial Deposit ($10) + Savings per Year ($260 * x)

So, Jeff will have saved $10 + $260x after x number of years.

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