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Given (x-1) is a factor of (2x³ +3x² - 4x-2) find all factors

User Keen
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Final answer:

To find all factors of the polynomial 2x³ + 3x² - 4x - 2, divide it by (x-1) to obtain the quotient 2x² + 5x + 2, which factors further into (2x + 1)(x + 2). Thus, the complete factorization of the polynomial is (x - 1)(2x + 1)(x + 2).

Step-by-step explanation:

To find all factors of the polynomial 2x³ +3x² - 4x - 2, given that (x-1) is a factor, we need to perform polynomial long division or use synthetic division to divide the polynomial by (x-1).

  • Set up the division:
  • Divide the first term of the polynomial by the first term of the divisor, and multiply the divisor by that quotient. Subtract the result from the polynomial.
  • Continue the process until you reach a remainder of 0.
  • This will give you a quotient of 2x² + 5x + 2.

Now, we look for factors of the quadratic equation 2x² + 5x + 2. This can be factored into (2x + 1)(x + 2).

The original polynomial can thus be expressed as the product of its factors: (x - 1)(2x + 1)(x + 2).

User Unbeli
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