Question

A car accelerates from rest and travels in the negative direction. The cars acceleration remains constant at -2.65 m/s². Sketch the position versus time, velocity versus time, and acceleration versus time graphs for this motion. It does not to include numerical values, i just need to show the shape of the curves with the appropriate direction information (positive or negative)

Answer 1

In the context of Physics, when a car accelerates from rest at a constant acceleration of -2.65 m/s², the acceleration vs. time graph is a horizontal line below the time axis, the velocity vs. time graph is a straight line with a negative slope, and the position vs. time graph is a downward-bending curve starting at the origin.

Step-by-step explanation:

The subject of this question is Physics, specifically kinematic graphs representing motion with constant acceleration. Since the car accelerates at a constant rate of -2.65 m/s² from rest in the negative direction, the acceleration vs. time graph will simply be a horizontal line below the time-axis, indicating a constant negative acceleration.

The velocity vs. time graph for this car will be a straight line starting at the origin and sloping downwards to the right, indicating an increase in velocity in the negative direction (negative slope) over time. The rate of change of velocity is constant because the acceleration is constant.

Finally, the position vs. time graph will be a curve that bends downwards, as the position of the car is changing at an increasing rate in the negative direction due to the negative acceleration. The curve will start at the origin since the car starts from rest.