Question

A boy pulls a sled across the snow. The coefficient of friction between the sled and the snow is 0.12. The mass of the sled is 22kg. If the boy applies a force of 150N to the sled, at what rate does it accelerate?

Answer 1

The sled accelerates at a rate of 5.64 m/s^2 when the boy applies a force of 150N, considering the coefficient of friction between the sled and the snow is 0.12 and the mass of the sled is 22kg.

Step-by-step explanation:

The question is asking for the rate of acceleration of a sled being pulled across snow, given specific forces and a coefficient of friction. First, we need to calculate the force of friction, which can be found using the formula Ffriction = μ * m * g, where μ is the coefficient of friction, m is the mass of the sled, and g is the acceleration due to gravity (approximated to 9.8 m/s2).

Then, we can find the net force acting on the sled by subtracting the force of friction from the applied force. The net force is used to calculate the acceleration through Newton's second law, F = ma, where F is the net force, m is the mass, and a is the acceleration.

First, calculate the force of friction: Ffriction = 0.12 * 22kg * 9.8 m/s2 = 25.8 N.

Then, find the net force: Net Force = Applied Force - Friction Force = 150N - 25.8 N = 124.2 N.

Finally, calculate the acceleration: Acceleration = Net Force / Mass = 124.2 N / 22 kg = 5.64 m/s2.

Therefore, the sled accelerates at a rate of 5.64 m/s2.