Question

A vial contains 2000 mg, which is to be used for two dosages. One patient is to be administered 660 mg more than another. How much should be administered to each?

Answer 1

patient 1 - 1330mg

patient 2 - 670mg

Step-by-step explanation:

1/2 of 660mg = 330mg

let's say that one full dosage is 1000mg, since half of the vial is 1000mg

we add the additional dose to the full dosage, 1000 + 330mg = 1330mg dose for the first patient.

we can figure out the second patient's dose by removing the first patient's dose from the capacity of the entire vial.

2000 - 1330 = 670mg

it is not possible to have completely even doses with this method, as a vial of 2660 mg would be required if the normal dose is 1000mg.

hope this helps

Answer 2

The first patient requires a dosage of 670 mg, while the second patient should receive 1330 mg from the vial, which in total uses up the available 2000 mg.

Step-by-step explanation:

The question requires us to determine how much of a medication should be administered to each of two patients from a vial containing a total of 2000 mg, given that one patient should receive 660 mg more than the other. This problem can be solved using simple algebra.

Let us represent the amount given to the patient who receives less medication as 'x' milligrams. Consequently, the other patient will then receive 'x + 660' milligrams.

Since the total medication available is 2000 mg, we can establish the following equation:

x + (x + 660) = 2000

Solving the equation:

1. 2x + 660 = 2000
2. 2x = 2000 - 660
3. 2x = 1340
4. x = 1340 / 2
5. x = 670 mg

Thus, the first patient should be administered 670 mg and the second patient should be administered 670 mg + 660 mg, which equals 1330 mg.