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In four o clock plants there are three phenotypes for flower color but only 2 alleles. In one population q2 = 0.169 and the population is assumed to be in hardy Weinberg equilibrium

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Final answer:

In four o'clock plants, determining genotypes and phenotypes under Hardy-Weinberg equilibrium involves using allele frequencies to calculate expected genotype numbers and observing phenotypic ratios to estimate the genetic structure of the population.

Step-by-step explanation:

The Hardy-Weinberg principle is a fundamental concept in population genetics which provides a mathematical baseline for comparing actual genetic structures in populations against a model where no evolution is occurring. When a population is in Hardy-Weinberg equilibrium, the allele and genotype frequencies are stable from generation to generation, unless specific forces such as selection, mutation, migration, genetic drift, or nonrandom mating are at work. Referring to the four o'clock plants, if it's assumed that the population is in Hardy-Weinberg equilibrium and given that the frequency of the homozygous recessive genotype (q2) = 0.169, we can ascertain the allele frequencies for this two-allele system. The square root of q2 = q = the frequency of the recessive allele, and since p + q = 1, we can solve for p, the frequency of the dominant allele. From there, we can determine the number of individuals expected to have each genotype using the Hardy-Weinberg formula (p2 + 2pq + q2 = 1).

Moreover, examining phenotypes, such as flower color observed in a population, allows us to utilize the Hardy-Weinberg principle to estimate genotype frequencies based on observable data. For instance, if the gene pool shows a certain phenotype more frequently, you can use the principle to calculate expected genotypic ratios and thus predict future phenotypic frequencies under the assumption of equilibrium.

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