Final answer:
To solve the equation h(t) = -33 when h(t)=2t-5, we set 2t - 5 to equal -33 and solve for t, which results in t = -14. However, if t represents time, this negative value would be unreasonable in a physical context and would thus be disregarded.
Step-by-step explanation:
We are asked to solve the equation h(t) = -33 when h(t)=2t-5. To find the value(s) of t when h(t) equals -33, we set up the equation 2t - 5 = -33 and solve for t.
Rearranging the terms gives us 2t = -33 + 5, which simplifies to 2t = -28. Dividing both sides by 2, we get t = -14.
To solve the equation h(t) = -33 when h(t) = 2t-5, we can set the two expressions equal to each other:
2t-5 = -33
Next, we can add 5 to both sides of the equation:
2t = -33 + 5
Simplifying, we get:
2t = -28
Finally, we can divide both sides of the equation by 2 to solve for t:
t = -28/2
So, the solution is:
t = -14
However, the referenced material seems to discuss different equations and contexts where t represents time, and reference is made to disregarding negative time solutions as they imply an event before the start of motion. In the given equation, if t represents time, then t = -14 would not make sense in terms of a physical scenario, and thus, if it were a time value, we would disregard this solution as well.