Final answer:
The acceleration of a car that increases its velocity uniformly from 20 m/s to 30 m/s over a distance of 100 m is 2.5 m/s². This is calculated using the kinematic equation v² = u² + 2as.
Step-by-step explanation:
To calculate the acceleration of a car that increased its velocity uniformly from 20 m/s to 30 m/s over a distance of 100 m, we can use the kinematic equation v² = u² + 2as, where 'v' is the final velocity, 'u' is the initial velocity, 'a' is the acceleration, and 's' is the distance covered. In this case:
Final velocity (v) = 30 m/s
Initial velocity (u) = 20 m/s
Distance (s) = 100 m
We need to solve for 'a' (acceleration). Rearranging the equation gives:
a = (v² - u²) / (2s)
Substituting the known values, we get:
a = (900 m²/s² - 400 m²/s²) / (200 m) = 500 m²/s² / 200 m = 2.5 m/s²
Therefore, the acceleration of the car during this period is 2.5 m/s².