Final answer:
For the quadratic functions provided, the vertices, axes of symmetry, minimum/maximum values, domains, and ranges were determined.
Step-by-step explanation:
For each of the given quadratic functions, we'll determine the Vertex, Axis of symmetry, Minimum or Maximum value, Domain, and Range:
f(x)=2(x−4)² +3
- The vertex, found by completing the square, is at (4, 3).
- Axis of symmetry: x=4.
- Since the coefficient of (x-4)2 is positive, this parabola has a minimum value at the vertex, which is 3.
- Domain: all real numbers (-∞, +∞).
- Range: [3, +∞) since it opens upwards.
f(x) = -(x + 3)² - 2.5
- Vertex: (-3, -2.5).
- Axis of symmetry: x=-3.
- Maximum value is -2.5 at the vertex because the parabola opens downwards.
- Domain: all real numbers (-∞, +∞).
- Range: (-∞, -2.5] since it opens downwards.
f(x) = -2(x - 6)²
- Vertex: (6, 0).
- Axis of symmetry: x=6.
- This function has a maximum value of 0 at the vertex.
- Domain: all real numbers (-∞, +∞).
- Range: (-∞, 0] because it opens downwards.