Question

At the Field Day event, you are participating in a water cannon activity, aiming to hit the principal. The water cannon is capable of launching water at a velocity of 42 m/s. Given that you have a limited time of 8.3 seconds to shoot and run, what is the minimum distance you must be from the principal for a direct hit?"

Answer 1

The minimum distance for a direct hit with a water cannon at 42 m/s with an 8.3 second time constraint is 348.6 meters.

Step-by-step explanation:

To determine the minimum distance from the principal you must be for a direct hit with a water cannon with a given time constraint, we need to calculate the horizontal distance covered by the water projectile within the allotted time. Assuming there's no vertical motion involved, and since it's merely a time-distance problem, we use the formula for distance in uniform motion:

distance = velocity × time

Given the velocity is 42 m/s and the time constraint is 8.3 seconds, we compute the distance as follows:

distance = (42 m/s) × (8.3 s) = 348.6 m

So, the minimum distance you must be from the principal for a direct hit, assuming the water can travel that far without any vertical displacement, is 348.6 meters.