Question

A backyard swimming pool holds 179 cubic yards (yd) of water. If the density of water is 1.00 g/mL, find themass of water in tons. (1 ton = 2000 lb) (lb = 453.59 g) (1 cm3 = 1 mL)

Answer 1

To find the mass of water in tons for a pool holding 179 cubic yards, we convert cubic yards to cubic centimeters, apply the density of water to find the mass in grams, convert the mass to pounds, and then to tons, resulting in approximately 151.02 tons of water.

Step-by-step explanation:

The question asks for the mass of water in tons when a backyard swimming pool holds 179 cubic yards of water, with the density of water given as 1.00 g/mL.

Firstly, we need to convert the volume from cubic yards to cubic centimeters (or milliliters), because the density is given in g/mL.

Since 1 cubic yard equals 764,554.857984 cubic centimeters (cc or cm3), we multiply 179 yd3 by this conversion factor:

179 yd3 x 764,554.857984 cm3/yd3 ≈ 136,955,870 cm3

Next, we use the density of water (1 g/cm3 = 1 g/mL) to find the mass in grams:

136,955,870 cm3 x 1 g/cm3 = 136,955,870 g

Then convert grams to pounds using the conversion 1 lb = 453.59 g:

136,955,870 g / 453.59 g/lb ≈ 302,038.88 lb

Finally, convert pounds to tons with 1 ton = 2000 lb:

302,038.88 lb / 2000 lb/ton ≈ 151.02 tons

Therefore, the mass of water in the swimming pool is approximately 151.02 tons.