Final answer:
Gay-Lussac's Law states that the pressure of a gas is directly proportional to its absolute temperature. Using the equation P1/T1 = P2/T2, we can determine the pressure of the cylinder at room temperature.
Step-by-step explanation:
Gay-Lussac's Law states that the pressure of a gas is directly proportional to its absolute temperature, assuming the volume and amount of gas remain constant. The equation for Gay-Lussac's Law is: P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature.
To solve the problem, we can use the equation: P1/T1 = P2/T2. Given that the initial pressure is 4.0 atm at 250 K, and we need to find the pressure at 293 K, we can set up the equation as follows:
4.0 atm / 250 K = P2 / 293 K
Cross-multiplying and solving for P2, we get:
P2 = (4.0 atm / 250 K) * 293 K = 4.68 atm
Therefore, the pressure of the same cylinder at room temperature, 293 K, is 4.68 atm. So, the correct answer is A. 4.68 atm.