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Gay-Lussac's Law: The pressure of a nitrogen gas, N₂, cylinder is measured at 250 K and found to be 4.0 atm. What is the pressure of the same cylinder at room temperature, 293 K?

A. 4.68 atm
B. 4.90 atm
C. 5.12 atm
D. 5.34 atm

1 Answer

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Final answer:

Gay-Lussac's Law states that the pressure of a gas is directly proportional to its absolute temperature. Using the equation P1/T1 = P2/T2, we can determine the pressure of the cylinder at room temperature.

Step-by-step explanation:

Gay-Lussac's Law states that the pressure of a gas is directly proportional to its absolute temperature, assuming the volume and amount of gas remain constant. The equation for Gay-Lussac's Law is: P1/T1 = P2/T2, where P1 and T1 are the initial pressure and temperature, and P2 and T2 are the final pressure and temperature.

To solve the problem, we can use the equation: P1/T1 = P2/T2. Given that the initial pressure is 4.0 atm at 250 K, and we need to find the pressure at 293 K, we can set up the equation as follows:

4.0 atm / 250 K = P2 / 293 K

Cross-multiplying and solving for P2, we get:

P2 = (4.0 atm / 250 K) * 293 K = 4.68 atm

Therefore, the pressure of the same cylinder at room temperature, 293 K, is 4.68 atm. So, the correct answer is A. 4.68 atm.

User Dominic Cronin
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