Final answer:
To find the equation of a line that is perpendicular to the given line and passes through the point (-6,5), we need to determine the slope of the given line and then use the negative reciprocal of that slope as the slope of the perpendicular line.
Step-by-step explanation:
To find the equation of a line that is perpendicular to the given line and passes through the point (-6,5), we need to determine the slope of the given line and then use the negative reciprocal of that slope as the slope of the perpendicular line.
To find the equation of a line that is perpendicular to the given line and passes through the point (-6,5), we need to determine the slope of the given line and then use the negative reciprocal of that slope as the slope of the perpendicular line.
Using the point-slope form of a linear equation, we can plug in the slope and the coordinates of the given point to find the equation of the perpendicular line. The equation of the line that is perpendicular to y = -2/7x + 4/7 and contains the point (-6,5) is y = 7/2x + 1.
The given line has a slope of -2/7, so the perpendicular line will have a slope of 7/2. Using the point-slope form of a linear equation, we can plug in the slope and the coordinates of the given point to find the equation of the perpendicular line.
Using the point (-6,5) and the slope 7/2, we get the equation y = 7/2x + 1 as the equation of the line that is perpendicular to y = -2/7x + 4/7 and contains the point (-6,5).