Final answer:
The rate of diffusion of a sample of ozonised oxygen is 0.98 times more than that of pure oxygen. The percentage of ozone by volume in the ozone by volume in the ozonised sample is: 63.93%.
Step-by-step explanation:
The rate of diffusion of a sample of ozonized oxygen is 0.98 times more than that of pure oxygen. To find the percentage of ozone by volume in the ozonized sample, we can use the fact that the rate of diffusion is directly proportional to the square root of the molecular mass of the gas.
Let's assume the molecular mass of pure oxygen is X and the molecular mass of ozone is Y. According to the given information, the rate of diffusion of ozonized oxygen is 0.98 times more than that of pure oxygen.
Using the proportionality relation, we can write:
√Y/√X = 0.98
Squaring both sides of the equation, we get:
Y/X = 0.98²
Simplifying, we find:
Y/X = 0.9604
Now, we know that the molecular mass of pure oxygen is approximately 32 g/mol.
Let's solve for Y:
Y = 0.9604 * 32
Y ≈ 30.6928 g/mol
Since ozone (O3) has a molecular mass of approximately 48 g/mol, we can find the percentage of ozone in the ozonized sample:
Percentage of ozone = (30.6928 / 48) * 100
Percentage of ozone ≈ 63.93%
Therefore, the percentage of ozone by volume in the ozonized sample is approximately 63.93%.