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Solve for C and D

- 3C + 4D = 5,
C + 5D = 2
(A) C = 1, D = 1
(B) C = -1, D = 2
(C) C = 2, D = -1
(D) C = 0, D = 1

User Sindyr
by
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1 Answer

5 votes

Final answer:

To solve the system of equations -3C + 4D = 5 and C + 5D = 2, use the method of substitution. The solution is C = -7/19 and D = 11/19.

Step-by-step explanation:

To solve the given system of equations, we will use the method of substitution.

From the second equation, we can express C in terms of D as C = 2 - 5D.

Substituting this value of C into the first equation, we get -3(2 - 5D) + 4D = 5.

Simplifying this equation gives us -6 + 15D + 4D = 5.

Combining like terms, we have 19D = 11.

Dividing both sides by 19, we get D = 11/19.

Now substitute this value of D back into the second equation to find C. C + 5(11/19) = 2.

Simplifying this equation gives us C = 2 - 55/19 = -7/19.

Therefore, the solution to the system of equations is C = -7/19 and D = 11/19.

User TankofVines
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