Final answer:
The acceleration of the bike is approximately 1.60 m/s².
Step-by-step explanation:
To determine the acceleration of the bike, we can use the kinematic equation v² = u²+2as, where v is the final velocity (8.0 m/s), u is the initial velocity (0 m/s, as the bike starts from rest), a is the acceleration, and s is the distance traveled (35.3 meters).
By rearranging the formula to solve for a, we get a= (v²-u²)/2s.
Substituting the given values, the calculation becomes
a = (8.0² - 0)/2 × 35.3 ≈ 1.60 m/s².
This result indicates that the bike's velocity increases by 1.60 meters per second each second as it accelerates uniformly.
a = (8.0² - 0)/2 × 35.3 ≈ 1.60 m/s².
The bike's acceleration during its uniform acceleration from rest to a speed of 8.0 m/s over a distance of 35.3 meters is approximately 1.60 m/s². This acceleration value provides insight into the rate at which the bike's velocity is changing during the specified motion.