Question

A student calibrated a 10-mL graduated cylinder using water and determined a density of 0.9981 g/mL at 21.8°C. Determine the percent error in this density determination.

Answer 1

The percent error in the density determination is 0.01%.

Step-by-step explanation:

To calculate the percent error in the density determination, we will compare the determined density (0.9981 g/mL) with the accepted value of the density of water at 21.8°C (0.9982 g/mL). The formula for percent error is:

Percent Error = | (Measured Value - Accepted Value) / Accepted Value | x 100%

Substituting the values:

Percent Error = | (0.9981 g/mL - 0.9982 g/mL) / 0.9982 g/mL | x 100% => Percent Error = 0.01%