Final answer:
In a truss structure with P1 = 600 lb and P2 = 400 lb, the horizontal component of the forces on each member is 100.0 N. The forces on the door are in tension and compression, with magnitudes of 200.0 N and 100.0 N respectively.
Step-by-step explanation:
To determine the force in each member of the truss and whether they are in tension or compression, we need to draw a free-body diagram of the truss. Given that P1 = 600 lb and P2 = 400 lb, we can start by calculating the horizontal component of these forces, which is equal to Ax = Bx = 100.0 N. The forces on the door are then 200.0 N in tension and 100.0 N in compression.