Question

Following the extraction 6 M HCl was added to both of the NaOH extracts, resulting in a precipitate. Provide the chemical reaction that occurred when HCl was added. For this reactions use hydronium in place of HCl as that is the active acid. Show all lone pair electrons and formal charges. What does the amount of precipitate in each tube indicate about the extraction procedure?

Answer 1

The chemical reaction between 6 M HCl and NaOH extract involves the formation of water as hydronium ions react with hydroxide ions. The amount of precipitate formed provides insight into the effectiveness of the extraction process.

Step-by-step explanation:

When 6 M HCl was added to the solution containing NaOH extract, the active acid component, hydronium ion (H3O+), reacted with hydroxide ions (OH-) to form water (H2O). The chemical reaction can be represented as:

H3O+(aq) + OH-(aq) → 2 H2O(l)

This reaction is an example of an acid-base neutralization, where the acid (HCl) and base (NaOH) react to form water and a salt (in this case, NaCl).

The amount of precipitate formed indicates the efficiency of the extraction procedure. If a large amount of precipitate is observed, it suggests a significant amount of the target compound was successfully extracted from the original mixture. Conversely, a small amount of precipitate could indicate an incomplete extraction.