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Write the conic and standard form equation of a circle that has a center at (-3, 2) and a radius of 7.

A) Conic: Circle, Standard Form: (x + 3)² + (y - 2)² = 49
B) Conic: Ellipse, Standard Form: (x + 3)²/49 + (y - 2)²/49 = 1
C) Conic: Hyperbola, Standard Form: (x + 3)(y - 2) = 7
D) Conic: Circle, Standard Form: (x - 3)² + (y + 2)² = 49

User Karola
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Final answer:

The equation of a circle with center at (-3, 2) and radius of 7 is written in standard form as (x + 3)² + (y - 2)² = 49, which corresponds to a conic section known as a circle.

Step-by-step explanation:

The correct answer to the question is A) Conic: Circle, Standard Form: (x + 3)² + (y - 2)² = 49. To write the equation of a circle in standard form, we use the formula (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius. Since we're given the center of the circle at (-3, 2) and a radius of 7, we plug these values into the formula and get (x - (-3))² + (y - 2)² = 7², which simplifies to (x + 3)² + (y - 2)² = 49. Therefore, the correct standard form equation of this circle is as stated in option A, which represents a conic section known as a circle.

User Bbholzbb
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