Final answer:
To stop a 1,048 kg car moving at 34 km/hr, the work required is equal to the car's initial kinetic energy, which, after calculations, turns out to be 46,789 J when rounded to the nearest whole number.
Step-by-step explanation:
To calculate the amount of work required to stop a 1,048 kg car moving with a speed of 34 km/hr, it is essential to use the work-energy theorem. This theorem states that the work done on an object is equal to the change in its kinetic energy. First, we convert the speed from km/hr to m/s:
34 km/hr = 34 * (1000 m / 3600 s) = 9.44 m/s
Next, we calculate the initial kinetic energy (KE) of the car using the formula KE = 1/2 * mass * velocity^2:
KE = 1/2 * 1,048 kg * (9.44 m/s)^2
KE = 1/2 * 1,048 kg * 89.1536 m^2/s^2
KE = 46,788.672 J (rounded to the nearest Joule as per the question's instructions)
Since stopping the car means reducing its kinetic energy to zero, the work required is equal to the car's initial kinetic energy, which is 46,789 J (rounded to the nearest whole number).