Final answer:
Ted will need 8 spoils of cable to provide enough for the 12 apartments, considering each apartment requires 60 meters of cable and each spoil holds 100 meters. The correct answer is option B .
Step-by-step explanation:
To find the smallest number of new spoils that Ted will need for this job, we need to divide the total cable length required by the length of cable in each spoil. The total cable length required for the 12 apartments is 60 meters x 12 = 720 meters. To find the number of new spoils, we divide 720 meters by the length of cable in each spoil, which is 100 meters: 720 meters ÷ 100 meters = 7.2 spoils. Since we cannot have a fraction of a spoil, Ted will need to round up to the next whole number, which is 8 spoils. Therefore, the smallest number of new spoils that Ted will need for this job is 8 spoils.
The question asks for the smallest number of cable spoils needed for a job that requires 60 meters of cable per apartment for a total of 12 apartments. Each spoil holds 100 meters of cable.
First, calculate the total amount of cable needed by multiplying the amount needed per apartment by the number of apartments:
60 meters/apartment × 12 apartments = 720 meters total.
Next, divide the total amount of cable needed by the amount held in each spoil to determine the number of spoils needed:
720 meters ÷ 100 meters/spoil = 7.2 spoils.
Since spoils cannot be purchased in fractions and Ted needs enough cable for the job, he will need to round up to the next whole number of spoils. Therefore, Ted needs 8 spoils.
The correct answer is Option B) 8 spoils.