Final answer:
To find the number of six-inch square tiles needed to tile a kitchen that's fifteen feet wide and eighteen feet long, convert the kitchen's dimensions to inches, calculate the area of the kitchen, and then divide by the area of one tile. The calculation shows that 1,080 tiles are required, which is not one of the provided answer choices.
Step-by-step explanation:
The question involves calculating the number of tiles needed to cover a floor area. Since the kitchen is fifteen feet wide and eighteen feet long, we first convert these measurements into inches, as the tile size is given in inches. There are 12 inches in a foot, so the kitchen is 180 inches (15 feet x 12 inches/foot) wide and 216 inches (18 feet x 12 inches/foot) long.
Next, we calculate the area of the kitchen in square inches by multiplying the width by the length: 180 inches x 216 inches = 38,880 square inches.
Each tile is six inches square, so the area of one tile is 6 inches x 6 inches = 36 square inches. To find out how many tiles are needed, divide the total area of the kitchen by the area of one tile: 38,880 square inches / 36 square inches per tile = 1,080 tiles.
Therefore, the correct answer is not provided in the choices A to D since none of these options match the calculation. A total of 1,080 six-inch square tiles would be needed to tile the kitchen floor.