Question

A dog is chasing a cat at a rate of 10 m/s and then starts chasing a bubble at 4 m/s. He decelerated at a rate of -2.3 m/s², how long did it take him to change what he was chasing?

Answer 1

The time it takes the dog to decelerate from 10 m/s to 4 m/s with a deceleration of -2.3 m/s² is 2.61 seconds.

Step-by-step explanation:

The question involves calculating the time it takes for a dog to decelerate from a chasing speed of 10 m/s to a slower speed of 4 m/s. We are told the dog decelerates at a rat of -2.3 m/s². Using the formula of final velocity (v) = initial velocity (u) + acceleration (a) x time (t), and re-arranging to solve for time yields t = (v - u) / a. Substituting the known values, we get t = (4 m/s - 10 m/s) / (-2.3 m/s²).

Time to decelerate will therefore be t = (-6 m/s) / (-2.3 m/s²) = 2.61 seconds (rounded to two decimal places). This calculation allows one to understand the time it takes to change from one velocity to another with a given deceleration.